A) \[{{10}^{6}}\]
B) zero
C) \[4\times {{10}^{6}}~~\]
D) \[4\times {{10}^{4}}\]
Correct Answer: C
Solution :
When electron is accelerated through a potential difference of V volts, then Kinetic energy = eV i.e. \[\frac{2}{1}m{{\upsilon }^{2}}=eV\] \[\Rightarrow \] \[\upsilon \sqrt{\left( \frac{2eV}{m} \right)}\] \[\therefore \] \[\upsilon =\sqrt{\left( \frac{2\times 1.6\times {{10}^{-19}}\times 45.5}{9.1\times {{10}^{-31}}} \right)}\] \[=4\times {{10}^{6}}m/\sec \]
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