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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2004

  • question_answer
    A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is 340ms , die distance between the cliffs is:

    A)  680 m

    B)  1700 m

    C)  340 m

    D)  1620 m

    Correct Answer: C

    Solution :

    Let the distance between the two cliffs be d. Since, the man is standing midway between the two cliffs, then the distance of man from either end is d/2. The distance travelled by sound (in producing an echo) \[2\times \frac{d}{2}=\upsilon \times t\] \[\Rightarrow \] \[d=340\times 1\] \[=340m\]


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