A) 2.4 cm
B) 2.4 mm
C) 1.2 mm
D) 1.2 cm
Correct Answer: B
Solution :
The distance between the first dark (minima) fringes on either side of the central maximum is twice the fringe width of either maximum or minimum. i.e. \[\beta =2\frac{D\lambda }{d}\] \[=\frac{2\times 2\times 600\times {{10}^{-9}}}{1\times {{10}^{-3}}}\] \[=2.4\times {{10}^{-3}}m\]You need to login to perform this action.
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