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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2004

  • question_answer
    Two equal forces (P each) act at a point inclined to each other at an angle of\[120{}^\circ \]. The magnitude of their resultant is:

    A)  P/2

    B)  P/4

    C)  P    

    D)  2P

    Correct Answer: C

    Solution :

    The resultant force of two equal forces \[=\sqrt{{{P}^{2}}+{{P}^{2}}+2P.P\cos {{120}^{o}}}\] \[=\sqrt{2{{P}^{2}}+2{{P}^{2}}\times \left( -\frac{1}{2} \right)}\] \[=\sqrt{2{{P}^{2}}-{{P}^{2}}}=\sqrt{{{P}^{2}}}=P\]


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