A) 0.6 A
B) 1.2 A
C) 0.9 A
D) 1.5 A
Correct Answer: C
Solution :
In the steady state, no current flows through the branch containing the capacitor. So, the equivalent circuit will be of the form as shown below : The effective resistance of the circuit is \[R=\frac{2\times 3}{2+3}+2.8\] \[=1.2+2.8=4\Omega \] The current through the ciruit is \[i=\frac{E}{R}=\frac{6}{4}=1.5A\] Let current \[{{i}_{1}}\]flows through \[2\Omega \]resistance. \[\therefore \] \[2\times {{i}_{1}}=(i-{{i}_{1}})\times 3\] \[\Rightarrow \] \[2{{i}_{1}}=(1.5-{{i}_{1}})\times 3\] \[\Rightarrow \] \[2{{i}_{1}}=4.5-3{{i}_{1}}\] \[\Rightarrow \] \[5{{i}_{1}}=4.5\] \[\therefore \] \[{{i}_{1}}=0.9A\]You need to login to perform this action.
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