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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2004

  • question_answer
    An artificial radioactive isotope gave \[_{7}^{14}N\] after two successive p-particle emissions. The number of neutrons in the parent nucleus must be:

    A) \[9\]               

    B) \[14\]

    C) \[5\]               

    D) \[7\]

    Correct Answer: A

    Solution :

    Atomic number increases by one after the emission of one P-particle. Hence, the parent nucleus (which on two successive P-emission gave \[_{7}{{N}^{14}}\]) must be \[_{5}{{X}^{14}}\]. Hence, number of neutrons in parent nucleus \[=14-5=9\]


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