A) \[1:8\]
B) \[1:4\]
C) \[4:1\]
D) \[8:1\]
Correct Answer: D
Solution :
\[2S{{O}_{2}}(g)+{{O}_{2}}(g)2S{{O}_{3}}(g)\] For this reaction, rate \[({{r}_{1}})=k[S{{O}_{2}}]_{1}^{2}{{[{{O}_{2}}]}_{1}}\] ?...(1) On doubling the volume of vessel, concentration would be half. Hence, rate \[({{r}_{2}})=k{{\left( \frac{{{[S{{O}_{2}}]}_{1}}}{2} \right)}^{2}}\left( \frac{{{[{{O}_{2}}]}_{1}}}{2} \right)=\frac{{{r}_{1}}}{8}\] \[\frac{{{r}_{1}}}{{{r}_{2}}}=8:1\]
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