2. Solved Papers
  3. CET Karnataka Medical

CET Karnataka Medical CET - Karnataka Medical Solved Paper-2005

  • question_answer
    In the circuit given \[E=6.0\]volt, \[{{R}_{1}}=\text{ }100\,\Omega \]\[{{R}_{2}}=\text{ }{{R}_{3}}50\,\Omega \],\[{{R}_{4}}=75\,\Omega \]. The equivalent resistance of the circuit, in ohms, is:

    A)  11.875

    B)  26.31

    C)  118.75

    D)  none of these

    Correct Answer: C

    Solution :

    \[{{R}_{2}},{{R}_{3}}\]and\[{{R}_{4}}\]are in parallel order, so their equivalent resistance \[\frac{1}{R}=\frac{1}{{{R}_{2}}}+\frac{1}{{{R}_{3}}}+\frac{1}{{{R}_{4}}}\] \[=\frac{1}{50}+\frac{1}{50}+\frac{1}{75}=\frac{30+30+20}{1500}\] \[=\frac{80}{1500}=\frac{4}{75}\] \[\therefore \]\[R=\frac{75}{4}\Omega \] \[R={{R}_{1}}+R\] \[=100+\frac{75}{4}\] \[=\frac{475}{4}\Omega \] \[=118.75\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner