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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2005

  • question_answer
    Molarity of \[0.2N\text{ }{{H}_{2}}S{{O}_{4}}\]is:

    A) \[0.2\]              

    B) \[0.4\]

    C) \[0.6\]             

    D) \[0.1\]

    Correct Answer: D

    Solution :

    Normality of acid = molarity \[\times \] basicity \[Molarity=\frac{N}{Bacicity}\] \[=\frac{0.2}{2}=0.1M\]


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