A) \[10\]
B) \[9\]
C) \[4\]
D) \[7\]
Correct Answer: A
Solution :
\[pOH=p{{K}_{b}}+\log \frac{[salt]}{[base]}\] (Hendersons equation) \[=5+\log \frac{0.02}{0.2}=5+\log \frac{1}{10}\] \[=5+(-1)=4\] \[pH=14-pOH=14-4=10\]You need to login to perform this action.
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