2. Solved Papers
  3. CET Karnataka Medical

CET Karnataka Medical CET - Karnataka Medical Solved Paper-2005

  • question_answer
    The electron in a hydrogen atom makes a transition from \[n={{n}_{1}}\]to \[n={{n}_{2}}\]state. The time period of the electron in the initial state \[\left( {{n}_{1}} \right)\] is eight times that in the final state\[\left( {{n}_{2}} \right)\]. The possible values of \[{{n}_{1}}\]and \[{{n}_{2}}\]are:

    A) \[{{n}_{1}}=8\],\[{{n}_{2}}=1\]

    B) \[{{n}_{1}}=4\], \[{{n}_{2}}=2\]

    C) \[{{n}_{1}}=2\],\[{{n}_{2}}=4\]

    D) \[{{n}_{1}}=1\], \[{{n}_{2}}=8\]

    Correct Answer: B

    Solution :

    In a hydrogen atom the time period is given by \[T\propto {{n}^{3}}\] \[\frac{{{T}_{1}}}{{{T}_{2}}}={{\left( \frac{{{n}_{1}}}{{{n}_{2}}} \right)}^{3}}\Rightarrow \frac{8}{1}={{\left( \frac{{{n}_{1}}}{{{n}_{2}}} \right)}^{3}}\] \[\therefore \] \[\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{2}{1}\] Thus, \[{{n}_{1}}=4\]and\[{{n}_{2}}=2\]


You need to login to perform this action.
You will be redirected in 3 sec spinner