CET Karnataka Medical CET - Karnataka Medical Solved Paper-2005

  • question_answer
    An air filled parallel plate condenser has a capacity of\[2\text{ }pF\]. The separation of the plates is doubled and the interspace between the plates is filled with wax. If the capacity is increased to\[6\text{ }pF\], the dielectric constant of wax is:

    A)  2

    B)  3

    C)  4

    D)  6

    Correct Answer: D

    Solution :

    Capacitance with air\[C=\frac{A{{\varepsilon }_{0}}}{d}\]When interspace between the plates is filled with wax, then \[C=\frac{KA{{\varepsilon }_{0}}}{2d}\] or \[C=\left( \frac{A{{\varepsilon }_{0}}}{d} \right)\frac{K}{2}\] or \[C=C\frac{K}{2}\] \[\therefore \] \[6=2.\frac{K}{2}\Rightarrow K=6\]


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