A) chloroform
B) chloral
C) methyl chloride
D) monochloroacetic acid
Correct Answer: B
Solution :
Molecular formula of \[A={{C}_{2}}C{{l}_{3}}OH\] As [A] reduces Fehlings solution and on oxidation gives a monocarboxylic acid [B]. It means [A] must be an aldehyde. \[CC{{l}_{3}}\underset{(A)}{\mathop{CHO}}\,\] This is further confirmed by the reaction \[{{C}_{2}}{{H}_{5}}OH+C{{l}_{2}}\xrightarrow[Oxidation]{[O]}C{{H}_{3}}CHO\] \[\xrightarrow[Chlorination]{[O]}CC{{l}_{3}}CHO\] A= Chloral \[[CC{{l}_{3}}CHO]\]You need to login to perform this action.
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