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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2005

  • question_answer
    If, in the reaction \[{{N}_{2}}{{O}_{4}}2N{{O}_{2}}\], x is, that part of \[{{N}_{2}}{{O}_{4}}\] which dissociates, then the number of molecules at equilibrium will be:

    A)  \[1\]                                     

    B) \[3\]                                                  

    C)  \[(1+x)\]                       

    D)  \[{{(1+x)}^{2}}\]                                    

    Correct Answer: C

    Solution :

    \[\underset{1-x}{\mathop{\underset{1}{\mathop{{{N}_{2}}{{O}_{4}}}}\,}}\,\underset{2x\,\,\,\,\,after\,\,discociatoon}{\mathop{\underset{0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,before\,dissociation}{\mathop{2N{{O}_{2}}}}\,}}\,\] Total number of moles at equilibrium \[=1+x+2x=1+x\]


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