A) \[[Cu{{(N{{H}_{3}})}_{4}}]S{{o}_{4}}\]
B) \[[Pt{{(N{{H}_{3}})}_{2}}C{{l}_{2}}]\]
C) \[[Ni{{(CO)}_{4}}]\]
D) \[{{K}_{3}}[Fe{{(CN)}_{6}}]\]
Correct Answer: C
Solution :
\[[Cu{{(NH)}_{4}}]S{{O}_{4}}\] Oxidation numbers of \[Cu\] \[\Rightarrow \] \[x+4\times 0-2=0\] \[x-2=0\] \[x=+2\] O.N of \[Cu=+2\] O.N of Pt in [Pt \[{{(N{{H}_{3}})}_{2}}C{{l}_{2}}\]] \[x+2\times 0+2\times -1=0\] \[x-2=0\] \[x=+2\] O.N of Ni in \[[Ni{{(CO)}_{4}}]\] \[x+4\times 0=0\] \[x=0\] O.N of Fe in \[{{K}_{3}}[Fe{{(CN)}_{6}}]\] \[3\times (+1)+x+6\times -1=0\] \[3+x-6=0\] \[x=+3\] \[\therefore \]\[[Ni{{(CO)}_{4}}]\] is zero valent compound
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