A) \[HSO_{4}^{-}\]
B) \[SO_{4}^{2-}\]
C) \[{{H}_{3}}{{O}^{+}}\]
D) \[C{{l}^{-}}\]
Correct Answer: A
Solution :
The species which can accept as well as donate \[{{H}^{+}}\] can act both as an acid and a base. \[\underset{base}{\mathop{HSO_{4}^{-}}}\,+{{H}^{+}}{{H}_{2}}S{{O}_{4}}\] \[\underset{acid}{\mathop{HSO_{4}^{-}}}\,SO_{4}^{2-}+{{H}^{+}}\]
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