A) \[{{375}^{o}}C\]
B) \[375K\]
C) \[273K\]
D) \[{{102}^{o}}C\]
Correct Answer: B
Solution :
\[\Delta S=16J\,mo{{l}^{-1}}\,{{K}^{-1}},\,\Delta {{H}_{p}}=6kJ\,mo{{l}^{-1}}\] \[{{T}_{b.p.}}=\frac{\Delta {{H}_{vapour}}}{\Delta {{S}_{vapour}}}=\frac{6\times 1000}{16}=375K\]
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