A) 11.875
B) 26.31
C) 118.75
D) none of these
Correct Answer: C
Solution :
\[{{R}_{2}},{{R}_{3}}\]and\[{{R}_{4}}\]are in parallel order, so their equivalent resistance \[\frac{1}{R}=\frac{1}{{{R}_{2}}}+\frac{1}{{{R}_{3}}}+\frac{1}{{{R}_{4}}}\] \[=\frac{1}{50}+\frac{1}{50}+\frac{1}{75}=\frac{30+30+20}{1500}\] \[=\frac{80}{1500}=\frac{4}{75}\] \[\therefore \]\[R=\frac{75}{4}\Omega \] \[R={{R}_{1}}+R\] \[=100+\frac{75}{4}\] \[=\frac{475}{4}\Omega \] \[=118.75\Omega \]You need to login to perform this action.
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