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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2006

  • question_answer
    The catalyst used in the preparation of an alkyl chloride by the action of dry \[HCl\] on an alcohol is:

    A)  anhydrous \[AlC{{l}_{3}}\]

    B)  \[FeC{{l}_{3}}\]

    C)  anyhydrous \[ZnC{{l}_{2}}\]

    D)  \[Cu\]

    Correct Answer: C

    Solution :

    \[-OH\] group is converted into \[-Cl\] group by \[SOC{{l}_{2}}\] or anhy  \[ZnC{{l}_{2}}\]/conc. \[HCl\] or \[HCl\] etc.


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