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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2006

  • question_answer
    A thin prism \[{{P}_{1}}\]with angle \[4{}^\circ \] made from a glass of refractive index 1.54 is combined with another thin prism \[{{P}_{2}}\]made from glass of refractive index 1.72 to produce dispersion without deviation. The angle of the prism \[\,{{P}_{2}}\]is:

    A) \[5.33{}^\circ \]

    B)  \[4{}^\circ \]

    C)  \[3{}^\circ \]

    D)  \[2.6{}^\circ \]

    Correct Answer: C

    Solution :

    For no deviation, \[(\mu -1)A+(\mu -1)A=0\] \[\Rightarrow \] \[A=-\frac{(\mu -1)A}{(\mu -1)}\] \[=-\frac{(1.54-1){{4}^{o}}}{(1.72-1)}\] \[=-{{3}^{o}}\] Negative sign implies that two prisms should be connected in opposition.


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