A) 1.06 pF
B) 4 pF
C) 6.36 pF
D) 12.72 pF
Correct Answer: B
Solution :
The given arrangement of nine plates is equivalent to the parallel combination of 8 capacitors. The capacity of each capacitor, \[C=\frac{{{\varepsilon }_{0}}A}{d}\] \[=\frac{8.854\times {{10}^{-12}}\times 5\times {{10}^{-4}}}{0.885\times {{10}^{-2}}}=0.5pF\] Hence, the capacity of 8 capacitors \[=8C=8\times 0.5=4pF\]
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