A) zero to \[+5\]
B) \[+1\] to \[+5\]
C) zero to \[-3\]
D) \[+2\] to \[+5\]
Correct Answer: A
Solution :
Bromine has zero oxidation state because it is in free state \[\overset{0}{\mathop{B{{r}_{2}}}}\,\xrightarrow{{}}BrO_{3}^{-}\] \[\overset{x}{\mathop{Br}}\,\overset{-2}{\mathop{{{O}_{3}}}}\,\] \[x+(-2\times 3)=-1\] \[x+(-6)=-1\] \[x=+6-1\] \[=+5\] So, oxidation number changes from 0 to \[+5\].
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