A) 20 %
B) 80 %
C) 95 %
D) 89 %
Correct Answer: C
Solution :
The strength of solution is given by\[c=\frac{\theta }{l\times s}\]where the symbols have their usual meanings. Here, \[\theta ={{19}^{o}},l=20cm=0.20m,\] \[S=0.5\deg \,{{m}^{2}}/kg\] \[\therefore \] \[c=\frac{19}{0.20\times 0.5}=190kg-{{m}^{-3}}\] The sugar sample dissolved in \[a\,{{m}^{3}}\]of water is 200 kg in which 190 kg is pure sugar. Therefore, purity is \[\frac{190}{200}\times 100=95%\]You need to login to perform this action.
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