A) 1
B) 0.60
C) 0.4
D) 1.5
Correct Answer: C
Solution :
We can simplify the network as shown : So, net resistance, \[R=2.4+1.6=4.0\Omega \] Therefore, current from the battery, \[i=\frac{V}{R}=\frac{4}{4}=1A\] Now from the circuit , \[4I=6I\] \[\Rightarrow \] \[I=\frac{3}{2}I\] but\[i=I=I+\frac{3}{2}I=\frac{5}{2}I\] \[\therefore \] \[1=\frac{5}{2}I\] \[\Rightarrow \] \[I=\frac{2}{5}=0.4A\]You need to login to perform this action.
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