CET Karnataka Medical CET - Karnataka Medical Solved Paper-2006

  • question_answer
    The concentration of a reactant X decreases from \[0.1M\]to \[0.005M\]in 40 minute. If the reaction follows 1 order kinetics, the rate of the reaction when the concentration of X is \[0.01M\]will be:

    A)  \[1.73\times {{10}^{-4}}\text{ }M\,mi{{n}^{-1}}\]

    B)  \[3.47\times {{10}^{-4}}\text{ }M\,mi{{n}^{-1}}\]

    C)  \[3.47\times {{10}^{-5}}\text{ }M\,mi{{n}^{-1}}\]

    D)  \[7.5\times {{10}^{-4}}\text{ }M\,mi{{n}^{-1}}\]

    Correct Answer: D

    Solution :

    \[k=\frac{2.303}{t}\log \frac{{{A}_{0}}}{A}\] \[=\frac{2.303}{40}\log \frac{0.1}{0.005}\] \[=\frac{2.303}{40}\log 20=0.075\] Rate of reaction when concentration of X is \[0.01M\]will be \[0.075\times 0.01=7.5\times {{10}^{-4}}M\,{{\min }^{-1}}\]


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