CET Karnataka Medical CET - Karnataka Medical Solved Paper-2006

  • question_answer
    Solubility product of a salt AS is \[1\times {{10}^{-8}}\text{ }{{M}^{2}}\]in a solution in which the concentration of \[{{A}^{+}}\] ions is  \[{{10}^{-3}}M\]. The salt will precipitate when the concentration of \[{{B}^{-}}\] ions is kept:

    A)  between \[{{10}^{-8}}M\]to \[{{10}^{-7}}M\]

    B)  between \[{{10}^{-7}}M\] to \[{{10}^{-8}}M\]

    C)  \[>{{10}^{-5}}M\]

    D)  \[<{{10}^{-5}}M\]

    Correct Answer: C

    Solution :

    A salt is precipitated only when the product of ionic concentration is more then its solubility product. \[{{K}_{sp}}=1\times {{10}^{-8}}\] \[[{{A}^{+}}]={{10}^{-3}}M\] \[[{{B}^{-}}]=\frac{1\times {{10}^{-8}}}{{{10}^{-3}}}={{10}^{-5}}M\] So, AB will be precipitated only when the concentration of \[[{{B}^{-}}]\] is more than\[{{10}^{-5}}M\].


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