A) \[f=\frac{qB}{2\pi m}\]
B) \[f=\frac{qB}{2\pi {{m}^{2}}}\]
C) \[f=\frac{2{{\pi }^{2}}m}{qB}\]
D) \[f=\frac{2\pi m}{qB}\]
Correct Answer: A
Solution :
Lorentz force = centripetal force ie, \[Bqv=\frac{m{{v}^{2}}}{r}\] \[\Rightarrow \] \[Bq=m\omega \] \[\Rightarrow \] \[Bq=m2\pi f\] (as \[v=r\omega \]) \[\therefore \] \[f=\frac{Bq}{2\pi m}\]You need to login to perform this action.
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