CET Karnataka Medical CET - Karnataka Medical Solved Paper-2007

  • question_answer
    A charged particle is moving in a magnetic field of strength B perpendicular to the direction of the field. If q and m denote the charge and mass of the particle respectively, then the frequency of rotation of the particle is

    A)  \[f=\frac{qB}{2\pi m}\]

    B)  \[f=\frac{qB}{2\pi {{m}^{2}}}\]

    C)  \[f=\frac{2{{\pi }^{2}}m}{qB}\]

    D)  \[f=\frac{2\pi m}{qB}\]

    Correct Answer: A

    Solution :

    Lorentz force = centripetal force ie, \[Bqv=\frac{m{{v}^{2}}}{r}\] \[\Rightarrow \] \[Bq=m\omega \] \[\Rightarrow \] \[Bq=m2\pi f\] (as \[v=r\omega \]) \[\therefore \] \[f=\frac{Bq}{2\pi m}\]


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