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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2007

  • question_answer
    What is the equivalent weight of \[SnC{{l}_{2}}\] in the following reaction \[SnC{{l}_{2}}+C{{l}_{2}}\xrightarrow{{}}SnC{{l}_{4}}\]

    A)  \[95\]           

    B)  \[45\]

    C)  \[60\]           

    D)  \[30\]

    Correct Answer: A

    Solution :

    \[\underset{190}{\mathop{SnC{{l}_{2}}}}\,+\underset{71}{\mathop{C{{l}_{2}}}}\,\xrightarrow{{}}SnC{{l}_{2}}\] \[\frac{190}{{{E}_{1}}}=\frac{71}{35.5}\] \[{{E}_{1}}=95\]


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