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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2007

  • question_answer
    The head lights of a jeep are 1.2 m apart. If the pupil of the eye of an observer has a diameter of mm and light of wavelength \[5896\overset{\text{o}}{\mathop{\text{A}}}\,\] is used, what should be the maximum distance of the jeep from the observer if the two head lights are just separated?

    A)  33.9 km

    B)  33.9 m

    C)  3.34 m

    D)  3.39 m

    Correct Answer: C

    Solution :

    Distance of jeep, \[x=\frac{D\times d}{1.22\times \lambda }\]where D = diameter of lens, d = separation between sources. \[\Rightarrow \] \[x=\frac{(2\times {{10}^{-3}})\times 1.2}{1.22\times 5896\times {{10}^{-10}}}\] \[=3336m\] \[\Rightarrow \] \[x=3.34km\]


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