A) 3 \[\beta \]-particles
B) 2 \[\beta \]-particles and 1 \[\alpha \]-particle
C) 2 \[\beta \]-particles and 1 \[\gamma \]-particle
D) 2 \[\beta \]-particles and 1 \[\beta \]-particle
Correct Answer: B
Solution :
To form its own isotope atomic number (Z) should remain same. So, the emission of one a-particle and two \[\text{ }\!\!\beta\!\!\text{ -}\]particles will maintain the Z same. where \[\alpha \text{-}\]particle \[{{=}_{2}}H{{e}^{4}};\] \[\text{ }\!\!\beta\!\!\text{ -}\]particle \[{{\text{=}}_{\text{-1}}}{{\text{ }\!\!\beta\!\!\text{ }}^{\text{0}}}\]
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