CET Karnataka Medical CET - Karnataka Medical Solved Paper-2007

  • question_answer
    The potential of the electric field produced by point charge at any point (x, y, z) is given by V = 3 x 2 + 5, where x, y are in metres and V is in volts. The intensity of the electric field at (-2,1,0) is

    A)  \[+17\text{ }V{{m}^{-1}}\]

    B)  \[-17\text{ }V{{m}^{-1}}\]

    C)  \[+12\text{ }V{{m}^{-1}}\]

    D)  \[-12\text{ }V{{m}^{-1}}\]

    Correct Answer: D

    Solution :

    Potential \[(V)=3{{x}^{2}}+5\] Intensity of the electric field \[=\frac{dV}{dx}=6x\] \[\therefore \] E at \[x=-2\] \[=6(-2)=-12V/m\]


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