A) 96 J
B) 216 J
C) 144 J
D) 360 J
Correct Answer: A
Solution :
Total mass of the shell = 20 kg Ratio of the masses of the fragments = 2: 3 \[\therefore \]Masses of the fragments are 8 kg and 12 kg now, according to the conservation of momentum \[{{m}_{1}}{{v}_{1}}={{m}_{2}}{{v}_{2}}\] \[\therefore \] \[8\times 6=12\times v\] v (velocity of the larger fragment) = 4 m/s Kinetic energy \[=\frac{1}{2}m{{v}^{2}}\] \[=\frac{1}{2}\times 12\times {{(4)}^{2}}=96J\]
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