A) 384 J
B) 144 J
C) 276 J
D) 452 J
Correct Answer: B
Solution :
At constant pressure, Heat required \[=n{{C}_{p}}\Delta T\] \[\Rightarrow \] \[310=2\times {{C}_{p}}\times (35-25)\] \[\Rightarrow \] \[{{C}_{p}}=\frac{310}{20}=15.5J/mol/K\] Similarly, at constant volume, Heat required \[=n{{C}_{v}}\Delta T\] \[=2({{C}_{p}}-R)\times (35-25)\] \[[\because {{C}_{p}}-{{C}_{v}}=R]\] \[=2\times (15.-8.3)\times 10\] \[=2\times 7.2\times 10\] \[=144J\]
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