A) 1 : 3
B) 3 : 1
C) 1 : 2
D) 2 : 1
Correct Answer: B
Solution :
As the current and the other factors are same for both the galvanometers \[N\propto \tan \theta \] \[\frac{{{N}_{1}}}{{{N}_{2}}}=\frac{\tan {{60}^{o}}}{\tan {{30}^{o}}}\] \[=\frac{\sqrt{3}}{1/\sqrt{3}}\] \[\Rightarrow \] \[\frac{{{N}_{1}}}{{{N}_{2}}}=3\]You need to login to perform this action.
You will be redirected in
3 sec