A) 20 kg-wt
B) 10 kg-wt
C) 10\[\sqrt{3}\]kg-wt
D) 20\[\sqrt{3}\] kg-wt
Correct Answer: A
Solution :
The situation is shown in figure At an angle of \[60{}^\circ \], \[T\cos \theta =mg\] \[T=\frac{mg}{\cos \theta }=\frac{10g}{\cos {{60}^{o}}}\] \[=\frac{10}{1/2}kg-qt\] \[=20kg-wt\]You need to login to perform this action.
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