A) 2 N
B) 4 N
C) 6 N
D) 8 N
Correct Answer: C
Solution :
Distance travelled by the body in \[{{n}^{th}}\] second is given by \[{{S}_{n}}=u+\frac{a}{2}(2n-1)\] \[5=u+\frac{a}{2}(2\times 1-)\] \[5=u+\frac{a}{2}\] ?(i) \[2=u+\frac{a}{2}(2\times 3-1)\] \[2=u+\frac{5}{2}a\] ?.(ii) Solving Eqs. (i) and (ii), we get\[a=-\frac{6}{4}m/{{s}^{2}}\] ie, body is decelerating mass = 4 kg and \[F=m\times a=4\times \frac{6}{4}=6N\]
You need to login to perform this action.
You will be redirected in
3 sec
