A) \[75{}^\circ C~\]
B) \[67{}^\circ C\]
C) \[25{}^\circ C~\]
D) \[33{}^\circ C\]
Correct Answer: A
Solution :
Temperature of interface\[\theta =\frac{{{K}_{1}}{{\theta }_{1}}{{l}_{2}}+{{K}_{2}}{{\theta }_{2}}{{l}_{1}}}{{{K}_{1}}{{l}_{2}}+{{K}_{2}}{{l}_{1}}}\] It is given that\[{{K}_{Cu}}=9{{K}_{s}}\] So, if \[{{S}_{s}}={{K}_{1}}=K,\] then \[{{K}_{Cu}}={{K}_{2}}=9K\] \[\Rightarrow \] \[\theta =\frac{9K\times 100\times 6+K\times 0\times 18}{9K\times 6+K\times 18}\] \[=\frac{5400K}{72K}={{75}^{o}}C\]
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