A) Position isomers
B) Chain isomers
C) Functional isomers
D) Optical isomers
Correct Answer: C
Solution :
\[\underset{({{C}_{2}}{{H}_{6}}O)}{\mathop{\underset{(alcohol)}{\mathop{\underset{Methoxy\,methane}{\mathop{C{{H}_{3}}OC{{H}_{3}}}}\,}}\,}}\,\] \[\underset{({{C}_{2}}{{H}_{6}}O)\,molecular\,formula}{\mathop{\underset{functional\,group}{\mathop{\underset{Ethanol\,(ether)}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,}}\,}}\,\] In methoxy methane and ethanol both molecular formula is same but functional groups are different, so they are functional isomers.
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