A) \[22.4d{{m}^{3}}\]
B) \[44.8d{{m}^{3}}\]
C) \[67.2\text{ }d{{m}^{3}}\]
D) \[11.2\text{ }d{{m}^{3}}\]
Correct Answer: C
Solution :
\[\underset{1mol}{\mathop{F{{e}_{2}}{{O}_{3}}}}\,+\underset{3mol}{\mathop{3CO}}\,\xrightarrow{{}}2Fe+3C{{O}_{2}}\] Volume of 1 mole carbon monoxide \[=22.4L\] (at STP) 1 mole of ferric oxide is reduced by = 3 moles of \[CO\] \[=3\times 22.4L\] of \[CO\] \[=67.2d{{m}^{3}}\] of \[CO\]
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