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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2008

  • question_answer
    n-propyl bromide on treating with alcoholic \[KOH\] produces

    A)  Propane       

    B)  propene

    C)  Propyne       

    D)  propanol

    Correct Answer: B

    Solution :

    Alcoholic \[KOH\] is a dehydrohalogenation reagent, so when n-propyl bromide is treated with alcoholic \[KOH\], propene is obtained. \[\underset{n-propyl\,bromide}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br}}\,+alc\,\,KOH\xrightarrow{{}}\] \[C{{H}_{3}}CH=\underset{\text{Propene}}{\mathop{C{{H}_{2}}}}\,+HBr\]


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