A) \[Zn/HCl\]
B) \[Sn/HCl\]
C) \[Zn-Hg/HCl\]
D) \[Pd/{{H}_{2}}\]
Correct Answer: D
Solution :
Alkynes are converted into alkenes by using Lindlars catalyst \[({{H}_{2}}/Pd)\] \[\underset{Alkyne}{\mathop{R-C=C-R}}\,\xrightarrow{{{H}_{2}}/Pd}\underset{cis\,alkene}{\mathop{R-\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,=\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,-R}}\,\]
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