A) \[300c{{m}^{3}}\]
B) \[200c{{m}^{3}}\]
C) \[500c{{m}^{3}}\]
D) \[400c{{m}^{3}}\]
Correct Answer: C
Solution :
No. of mill moles of \[Ca{{(OH)}_{2}}=50\times 0.5=25\] No. of mill moles of \[CaC{{O}_{3}}=25\] No. of mill equivalents of \[CaC{{O}_{3}}=50\] \[\therefore \] Volume of \[0.1N\,HCl=\frac{50}{0.1}=500c{{m}^{3}}\]
You need to login to perform this action.
You will be redirected in
3 sec
