A) \[0.82atm\]
B) \[0.52atm\]
C) \[0.21atm\]
D) \[0.41atm\]
Correct Answer: D
Solution :
\[\begin{align} & Initial \\ & At\,equilibriu\underset{=2}{\mathop{m\underset{(5-3)}{\mathop{\underset{5}{\mathop{2S{{O}_{2}}(g)}}\,}}\,}}\,+\underset{=3.5}{\mathop{\underset{(5-1.5)}{\mathop{\underset{5}{\mathop{{{O}_{2}}(g)}}\,}}\,}}\,\underset{3}{\mathop{\underset{0}{\mathop{2S{{O}_{3}}(g)}}\,}}\, \\ \end{align}\]\[\therefore \] \[p{{O}_{2}}=\frac{3.5\times 1}{8.5}=0.41atm\]You need to login to perform this action.
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