CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    A body of mass m moving along a straight line covers half the distance with a speed of 2 ms-1. The remaining half of the distance is covered in two equal time intervals with a speed of 3 ms-1 and 5 ms-1 respectively. The average speed of the particle for the entire journey is

    A)  \[\frac{3}{8}m{{s}^{-1}}\]          

    B)  \[\frac{8}{3}m{{s}^{-1}}\]

    C)  \[\frac{4}{3}m{{s}^{-1}}\]

    D)  \[\frac{16}{3}m{{s}^{-1}}\]

    Correct Answer: B

    Solution :

    Let the total distance travelled by the body is 2S. If \[{{t}_{1}}\]is the time taken by the body to travel first half of the distance, then\[{{t}_{1}}=\frac{S}{2}\] Let \[{{t}_{2}}\] be the time taken by the body for each time interval for the remaining half journey. \[\therefore \] \[S=3{{t}_{2}}+5{{t}_{2}}=8{{t}_{2}}\] So, average speed\[=\frac{\text{Total distance travelled}}{\text{Total}\,\text{time}\,\text{taken}}\] \[=\frac{2S}{{{t}_{1}}+2{{t}_{2}}}\] \[=\frac{2S}{\frac{S}{2}+\frac{S}{4}}\] \[=\frac{8}{3}m{{s}^{-1}}\]


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