A) \[65{}^\circ C\]
B) \[70{}^\circ C\]
C) \[60{}^\circ C\]
D) \[75{}^\circ C\]
Correct Answer: A
Solution :
Let the final temperature of the mixture be t Heat lost by water at 80°C \[=ms\Delta t\] \[=0.1\times {{10}^{3}}\times {{s}_{water}}\times ({{80}^{o}}-t)\] \[(\because m=V\times d=0.1\times {{10}^{3}}kg)\] Heat gained by water at 60°C \[=0.3\times {{10}^{3}}\times {{s}_{water}}\times (t-{{60}^{o}})\] According to principle of calorimetry Heat lost = Heat gained \[\therefore \]\[0.1\times {{10}^{3}}{{s}_{water}}\times ({{80}^{o}}-t)\] \[=0.3\times {{10}^{3}}\times {{s}_{water}}\times (t-{{60}^{o}})\] or \[({{80}^{o}}-t)=3\times (t-{{60}^{o}})\] or \[4t={{260}^{o}}\] or \[t={{65}^{o}}C\]
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