A) 12.2 m
B) 24.2 m
C) 2.44 m
D) 1.22 m
Correct Answer: C
Solution :
According to Rayleighs criterion,\[\theta =\frac{1.22\lambda }{{{d}_{e}}}\] where \[\lambda =\] wavelength of light, \[{{d}_{e}}=\]diameter of the pupil of the eye \[\therefore \]\[\theta =\frac{1.22\times 500\times {{10}^{-9}}}{2.5\times {{10}^{-3}}}=2.44\times {{10}^{-4}}\]radianYou need to login to perform this action.
You will be redirected in
3 sec