question_answer

A resistor and a capacitor are connected in series with an AC source. If the potential drop across the capacitor is 5 V and that across resistor is 12 V, then applied voltage is

A)  13 V            

B)  17 V

C)  5 V              

D)  12 V

Correct Answer: A

Solution :

Let the applied voltage be V volt. Here,\[{{V}_{R}}=12V,{{V}_{C}}=5V\] \[\therefore \] \[V=\sqrt{V_{R}^{2}+V_{C}^{2}}=\sqrt{{{(12)}^{2}}+{{(5)}^{2}}}\] \[\sqrt{144+25}=\sqrt{169=}13V\]