CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    \[y=3\sin \pi \left( \frac{t}{2}-\frac{x}{4} \right)\]represents an equation of a progressive wave, where t is in second and \[x\] is in metre. The distance travelled by the wave in 5 s is

    A)  8 m             

    B)  10 m

    C)  5 m              

    D)  32 m

    Correct Answer: B

    Solution :

    The given equation of a progressive wave is \[y=3\sin \pi \left( \frac{t}{2}-\frac{x}{4} \right)=3\sin 2\pi \left( \frac{t}{4}-\frac{x}{8} \right)\] The standard equation of a progressive wave is \[y={{y}_{0}}\sin 2\pi \left( \frac{t}{T}-\frac{x}{\lambda } \right)\] Comparing these two equations, we get \[T=4s,\lambda =8m\] \[\therefore \]Velocity of wave,\[v=\frac{\lambda }{T}=\frac{8}{4}=2m{{s}^{-1}}\] Distance travelled by wave in time t is \[s=vt\]or      \[s=2\times 5=10m\]


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