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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    The electric potential at any point x, y, z in metres is given by\[V=\text{ }3{{x}^{2}}\]. The electric field at a point (2, 0, 1) is

    A)  \[12\text{ }V{{m}^{-1}}\]

    B)  \[-6\text{ }V{{m}^{-1}}\]

    C)  \[6V{{m}^{-1}}\]

    D)  \[-12V{{m}^{-1}}\]

    Correct Answer: D

    Solution :

    Here, electric potential \[V=3{{x}^{2}}\] Electric field, \[E=-\frac{\partial V}{\partial x}=-\frac{\partial }{\partial x}(3{{x}^{2}})=-6x\] \[\therefore \] \[E(2,0,1)=-12\,V{{m}^{-1}}\]


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