| \[[AB]\,mol\,\,d{{m}^{-3}}\] | Rate of decomposition of AB in \[mol\,d{{m}^{-3}}\,{{s}^{-1}}\] |
| \[0.20\] | \[2.75\times {{10}^{-8}}\] |
| \[0.40\] | \[11.0\times {{10}^{-8}}\] |
| \[0.60\] | \[24.75\times {{10}^{-8}}\] |
A) \[1.5\]
B) \[0\]
C) \[1\]
D) \[2\]
Correct Answer: D
Solution :
\[AB\xrightarrow{{}}\text{Product}\] Rate \[=k{{[AB]}^{n}}\] \[{{(Rate)}_{1}}=k{{[0.20]}^{n}}=2.75\times {{10}^{-8}}\].....(i) \[{{(Rate)}_{2}}=k{{[0.40]}^{n}}=11.0\times {{10}^{-8}}\] ?..(ii) Dividing Eq. (ii) by Eq. (i), \[\frac{{{(Rate)}_{2}}}{{{(Rate)}_{1}}}=\frac{k{{[0.40]}^{n}}}{k{{[0.20]}^{n}}}=\frac{11.0\times {{10}^{-8}}}{2.75\times {{10}^{-8}}}\] \[{{2}^{n}}=4\] or \[{{2}^{n}}={{2}^{2}}\] Hence, \[n=2\]
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